-2q^2+8q-8=0

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Solution for -2q^2+8q-8=0 equation: 



-2q^2+8q-8=0

a = -2; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-2)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-8}{-4}=+2$

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